-3x^2+35x-100=3x-36+x^2

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Solution for -3x^2+35x-100=3x-36+x^2 equation:



-3x^2+35x-100=3x-36+x^2
We move all terms to the left:
-3x^2+35x-100-(3x-36+x^2)=0
We get rid of parentheses
-3x^2-x^2-3x+35x+36-100=0
We add all the numbers together, and all the variables
-4x^2+32x-64=0
a = -4; b = 32; c = -64;
Δ = b2-4ac
Δ = 322-4·(-4)·(-64)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-32}{-8}=+4$

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